x^2+22x-63=0

Solution for x^2+22x-63=0 equation:

x^2+22x-63=0

a = 1; b = 22; c = -63;
Δ = b2-4ac
Δ = 222-4·1·(-63)
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-4\sqrt{46}}{2*1}=\frac{-22-4\sqrt{46}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+4\sqrt{46}}{2*1}=\frac{-22+4\sqrt{46}}{2}
$